using Newtonsoft.Json

首先添加Newtonsoft.Json的引用


1.JSON序列化


string JsonStr= JsonConvert.SerializeObject(Entity);


public class RecordResult

{

    [JsonProperty("status")]

    public int Status { get; set; }

    [JsonProperty("error")]

    public int Error { get; set; }

}

 

RecordResult result = new RecordResult();

 

result.Status = 1;

 

result.Error = "Error message";

 

string jsonStr = JsonConvert.SerializeObject(result);

2.JSON反序列化

Class model = JsonConvert.DeserializeObject<Class>(jsonstr);


var result = (RecordResult)JsonConvert.DeserializeObject(jsonstring, typeof(RecordResult))

 

//或者

 

var result = JsonConvert.DeserializeObject<RecordResult>(jsonstring)